Question: Given the recurrence relation where a 0 =1 a 0 =1 and a_n=a_{n-1}+a_{n-2}+...+a1+a0+1 for n1, use strong induction to prove that a n =2 n

Given the recurrence relation where a0=1

a0=1 and a_n=a_{n-1}+a_{n-2}+...+a1+a0+1

for n1, use strong induction to prove that an=2n is a solution to the given recurrence relation.

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