Given these two lines, D1: x=k y=2+k Z=3-k D2: (x,y,z)=(-1,5,5)+1(1,-3,-2) a) what is the relative position...

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Given these two lines, D1: x=k y=2+k Z=3-k D2: (x,y,z)=(-1,5,5)+1(1,-3,-2) a) what is the relative position of these two lines? b) what is the angle formed by the two lines? c)If both lines are secant, what are the coordinates of their intersection point? If, otherwise, they are parallel or they are not coplanar and not parallel, determine the distance that separates them. Given these two lines, D1: x=k y=2+k Z=3-k D2: (x,y,z)=(-1,5,5)+1(1,-3,-2) a) what is the relative position of these two lines? b) what is the angle formed by the two lines? c)If both lines are secant, what are the coordinates of their intersection point? If, otherwise, they are parallel or they are not coplanar and not parallel, determine the distance that separates them.

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Solution a As see based on point and vectors of line both seems intersect to each other ... View the full answer