Given two version numbers, version$1$ and version$2,$ compare them.

Version numbers consist of one or more revisions joined by a dot $\text{'}.\text{'}.$ Each revision consists of digits and may contain leading zeros. Every revision contains at least one character. Revisions are $0-$indexed from left to right, with the leftmost revision being revision $0,$ the next revision being revision $1,$ and so on$.$ For example $2\mathrm{.}5\mathrm{.}33$ and $0\mathrm{.}1$ are valid version numbers.

To compare version numbers, compare their revisions in left$-$to$-$right order. Revisions are compared using their integer value ignoring any leading zeros. This means that revisions $1$ and $001$ are considered equal. If a version number does not specify a revision at an index, then treat the revision as $0.$ For example, version $1\mathrm{.}0$ is less than version $1\mathrm{.}1$ because their revision $0$s are the same, but their revision $1$s are $0$ and $1$ respectively, and $0<1.$

class Solution $\{$

public int compareVersion$($String version$1,$ String version$2)\{$

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