Question: GJ 0 7 1 . ) ( A ) ( R ) ( S ) Ror Sin : ke / k = 1 . 2

GJ07
1.)(A)(R)(S) Ror Sin : ke/k =1.25 GHNH + CH4OH CH3NHC,H,+ HO (A)(8)(R) CH,NHC2H5+ C,H,OH" CH.NIC.Ms+ H30(R)(B)(5)+ a) b)70%21 MFR

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