Question: GK 1 5 CE 2 1 0 6 A ( ) ( W ) ( 1 ) dQ - W = du dW = PdV

GK15
CE2106 A ()(W)(1) dQ-W = du dW = PdV dU = CydT : = R/CP 1=-R/C4(7)(b)(i)(ii)

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