Question: Gmail mall LTE 20:39 docs.google.com y = log ( cos(2x) ) ; y' = * 2 tan ( 2x ) / In (10) O -

Gmail mall LTE 20:39 docs.google.com y = log ( cos(2x) ) ; y' = * 2 tan ( 2x ) / In (10) O - 2 tan ( 2x ) / In (10) 2 cot ( 2x ) / In (10) O - 2 cot ( 2x ) / In (10) O NONE OF THE ABOVE cos 2y = (X^2) + 4 ; y' =* O - x / sin (2y) 2x / sin ( 2y) - 2x / sin (2y) 2x / 2 sin y ONONE OF THE ABOVE

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