Question: Grain Grain Diameter 2 ( m m ) : = 6 . 3 0 E - 0 3 Yield Stress 2 ( M P a

Grain Grain Diameter 2(mm):=6.30E-03
Yield Stress 2(MPa):=272
Specimen 1 Initial Radius (mm): =19
Specimen 1 Final Radius (mm): =14
Specimen 2 Initial Radius (mm): =7
Problem 1 Part A:
=KTn
is 860MPa(125,000). Calculate the value of n .(Write your answer with 2 decimal places)
Your Answer =
icorrect.
Problem 1 Part B:
=KTn
is 860 MPa (125,000). Calculate the true strain for this material at the applied true stress listed above. (Write your answer to the thousandths place 0.000)
Your Answer =
Incorrect,
Problem 2:
For pure metals, the recrystallization temperature is normally about x*Tm, where Tm is the melting temperature, what is x?Problem 2:
For pure metals, the recrystallization temperature is normally about x*Tm, where Tm is the melting temperature, what is x ?
Your Answer =4
Incorrect.
Problem 3:
The yield strength for an alloy that has an average grain diameter, d 1, is listed Tabove as Yield Stress 1. At a grain diameter of d2, the yield strength increases Yield Stress 2. At what grain diameter, in mm, will the yield st
be 217 MPa ?(Answer to the ten thousands place 0.0000)
Your Answer =
Grain Grain Diameter 2 ( m m ) : = 6 . 3 0 E - 0

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