Graph the set of points whose polar coordinates satisfy the equation $r=4$ and the inequality $0.$

Find the point on the parabola $(16,-\frac{1}{2})(16,-\frac{1}{2})x=-t,y=-t^2,-,$ closest $to$ the point $(16,-\frac{1}{2}).$

$(Hint$: Minimize the square $of$ the distance $as$ a function $oft.)$

The point $on$ the given parabola closest $to$ the point $(16,-\frac{1}{2})is$

$(Simplify$ your answer. Type $an$ ordered pair.$)$

Find the point on the parabola $(16,-\frac{1}{2})(16,-\frac{1}{2})x=-t,y=-t^2,-,$ closest $to$ the point $(16,-\frac{1}{2}).$

$(Hint$: Minimize the square $of$ the distance $as$ a function $oft.)$

The point $on$ the given parabola closest $to$ the point $(16,-\frac{1}{2})is$

$(Simplify$ your answer. Type $an$ ordered pair.$)$

Find the point on the parabola $(16,-\frac{1}{2})(16,-\frac{1}{2})x=-t,y=-t^2,-,$ closest $to$ the point $(16,-\frac{1}{2}).$

$(Hint$: Minimize the square $of$ the distance $as$ a function $oft.)$

The point $on$ the given parabola closest $to$ the point $(16,-\frac{1}{2})is$

$(Simplify$ your answer. Type $an$ ordered pair.$)$

Find the point on the parabola $(16,-\frac{1}{2})(16,-\frac{1}{2})x=-t,y=-t^2,-,$ closest $to$ the point $(16,-\frac{1}{2}).$

$(Hint$: Minimize the square $of$ the distance $as$ a function $oft.)$

The point $on$ the given parabola closest $to$ the point $(16,-\frac{1}{2})is$

$(Simplify$ your answer. Type $an$ ordered pair.$)$