Question: Graphical Solution of Two Variable Linear Programs (Objective Function Minimize X0) In addition, the equation for the number of intersection is= number of constraints* number

Graphical Solution of Two Variable LinearGraphical Solution of Two Variable Linear Programs (Objective Function Minimize X0)

In addition, the equation for the number of intersection is= number of constraints* number of constraints-1 / 2= 7*6/2= 21 intersections in the graph.

(NOTE: I posted this question before and it was solved wrong because they did not lengthen equation 1& 2 " I Will attach the solution for the previous instructor & I will attach my graph too. ," THANK YOU )

In The attachment i divide it to 3 parts First Part Question/ Second Part Previous Answer/ Third Part My Graph.

Thank You

Second Part (PREVIOUS SOLUTION) Objective of Xo = x, +3tr Sub To, 32, 6x2=12 -32, + 122 12 - 2 +1.5%, 29 - 9x + 622 = 18 - 3 LT > Fourite 6,2.67 A eg? 32, put 26,20 6*2 =12 6x =12x AAL 4 5 3 6 7 First Part (QUESTION) objective Function Minimize Xo Xo = x, + 3X2 subject to: () 3X; - 6x2

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