Question: h(0) =3, h (0) = 0, h (1) = 4, h(1) = 0, g(0) = 1, g' (0) = 2, f'(1) = 1. Ify =


h(0) =3, h (0) = 0, h (1) = 4, h(1) = 0, g(0) = 1, g' (0) = 2, f'(1) = 1. Ify = f(g(h(x))), find y (1). [5 points] Let y be given implicitly as a differentiable function of r by the relation 213 +3xy-y? = 2. Find dy/dax at the point where r = 1, and y = 0. [6 points] A differentiable function f with a differentiable inverse function F has the values f(1) = 0
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