Question: HASKELL Using foldl, define a function num2int :: [Int] -> Int -> Int that converts a list of numbers and the number n into an

HASKELL

HASKELL Using foldl, define a function num2int :: [Int] -> Int ->

Using foldl, define a function num2int :: [Int] -> Int -> Int that converts a list of numbers and the number n into an integer of base n. >num2int [3,4,5,6] 10 3456 >num2int (1,1,0,1,0,0,0,1,0,1,0,1,1,0] 2 3456 num2int :: [Int] -> Int -> Int num2int x y = foldl (\acc (a,b) -> __a__ + b*y^a) 0 cb__ (xy->(x,y)) [0..] Cc_x) 1. Choose the appropriate word to fill blank (10 Puan) _a__ tail head \ XS

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