Have you ever noticed that when you buy a computer, the hard drive always seems a little smaller than what is advertised? That is because hardware manufacturers sell disk drives using the metric system, while computers use base $2.$ Therefore, a megabyte is sold as $1$ million bytes $({10}^6)$ instead of as $,$ or $($:$2^{20}\}$ bytes. Likewise, a gigabyte is sold as one billion bytes $({10}^9)$ bytes, instead of the $1,073,741,824($or $2^{30})$ bytes. However, since computers still interpret information as powers of $2,$ the hard drive capacity understood by the computer is much less. Today, the "traditional" gigabyte that was in powers of two is known as a gibibyte $($GiB$),$ to distinguish it from the metric version of Gigabyte. Likewise, $2^{20}$ is referred to as a mebibyte $($MiB$).$ To summarize, $1GB={10}^9$ bytes, while $1$GiB is $2^{30}$ bytes; $1MB={10}^6$ bytes, while $1$MiB$=2^{20}$ bytes.

Write a procedure called data$\_$lost $()$ that asks the user for the size of a purchased hard drive $($in Gigabytes$).$ Your procedure should then calculate the corresponding number of bytes in gibibytes and the remainder in mebibytes, and output that, along with the number of theoretical bytes lost. You may assume that the user always inputs an integer. Use the built$-$in function round $()$ to round the remaining mebibytes to the nearest whole number. Sample usage is shown below:

Sample Input$/$Output $1$

Please enter drive size: $300$

The drive is actually $279$ GiB and $406$MiB

This represents a loss of $20$GiB and $618$MiB

Sample Input$/$Output $2$

Please enter drive size: $500$

The drive is actually $465$GiB and $677$MiB

This represents a loss of $34$GiB and $347$MiB