Question: he general solution to the second - order differential equation d 2 ydt 2 2 dydt + 7 y = 0 is in the form

he general solution to the second-order differential equation d2ydt22dydt+7y=0 is in the form y(x)=ex(c1cosx+c2sinx). Find the values of and , where >0.
Answer: = and =

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