Hello can you help me find the P value and the hypothesis for a chi square test for independence?

Chi-Square Tests

Value

df

Asymptotic Significance (2-sided)

Pearson Chi-Square

1.969^a

2

.374

Likelihood Ratio

1.980

2

.372

Linear-by-Linear Association

.162

1

.687

N of Valid Cases

28

a. 4 cells (66.7%) have expected count less than 5. The minimum expected count is 3.43.

Different_Majors * Class_Time_Preferences Crosstabulation

Class_Time_Preferences

Total

Morning

Afternoon

Different_Majors

Engineering

Count

3

7

10

Expected Count

4.3

5.7

10.0

% within Different_Majors

30.0%

70.0%

100.0%

% within Class_Time_Preferences

25.0%

43.8%

35.7%

Psychology

Count

6

4

10

Expected Count

4.3

5.7

10.0

% within Different_Majors

60.0%

40.0%

100.0%

% within Class_Time_Preferences

50.0%

25.0%

35.7%

Business

Count

3

5

8

Expected Count

3.4

4.6

8.0

% within Different_Majors

37.5%

62.5%

100.0%

% within Class_Time_Preferences

25.0%

31.3%

28.6%

Total

Count

12

16

28

Expected Count

12.0

16.0

28.0

% within Different_Majors

42.9%

57.1%

100.0%

% within Class_Time_Preferences

100.0%

100.0%

100.0%