Question: Hello, I am unable to code any of this program besides simply the skeleton code for how it should run as I have not learned

Hello, I am unable to code any of this program besides simply the skeleton code for how it should run as I have not learned this topic yet.

For each of the following, please write C++ statements that perform the specified task.

Declare an array of type unsigned int called values with five elements, and initialize the elements to the even integers from 2 to 10. Assume that the symbolic constant SIZE has been defined as 5.

#define SIZE 5

unsigned int values[SIZE] = {2,4,6,8,10};

Declare a pointer vPtr that points to an object of type unsigned int.

int *vPtr;

Use a for statement to print the elements of array values using array subscript notation.

Use a for statement to print the elements of array values using pointer / offset notation.

Use a for statement to print the elements of array values using pointer / offset notation with the array name as the pointer.

Use a for statement to print the elements of array values by subscripting the pointer vPtr.

Use the address-of operator & to display the addresses of all elements in the array.

Thank you ahead of time for your help.

Here is the skeleton code for the program:

#include

#include

#define SIZE 5

using namespace std;

int main()

{

int values[SIZE] = {2,4,6,8,10};

int *vPtr = values;

//Question 1.

cout << " Question 1 output ";

cout << "Array Subscript Notation" << endl;

for ( int i = 0; i < SIZE ; i++ )

{

cout << "values[" << i << "] = "<< values[ i ] << endl;

}

//Question 2.

cout << " Question 2 output ";

cout << "Pointer / offset notation." << endl;

// Add code here

//Question 3

cout << " Question 3 output ";

cout << "Pointer/offset notation where the pointer is the array name ";

// Add code here

//Question 4

cout << " Question 4 output ";

cout << " Pointer subscript notation ";

// Add code here

//Question 5

cout << " Question 5 output ";

cout << " Address-of operator ";

// Add code here

return 0;

}

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