Hello, please answer and explain :

You know it would be interesting to find the thermal coefficient of resistivity (?) for both metals. You take your trusty ohmmeter (what measures resistance), connect its probes to the ends of the aluminum coil, and start taking your measurements. To lower the temperature of the coil below room temperature (?0 = 20 C), you dip it in cold water. To increase its temperature, you blow hot air with a hair dryer. You repeat the same measurements for the brass wire coil. Your measurements are recorded in Table 1.

Table 1 - Resistance values for aluminum and brass wire at different temperatures

\faccepted - experimental "% error= "| x 100% accepted\f9 TX Linear Fit for: Data Set | Resistance Laiton R.Laiton = mx+b m (Slope): 0.01872 0/C b (Y-Intercept): 8.798 0 Correlation: 0.9976 RMSE: 0.02294 0 8 Resistance Aluminium () Resistance Laiton () Linear Fit for: Data Set | Resistance Aluminium R. Al = mx+b m (Slope): 0.02513 0/C b (Y-Intercept): 6.495 0 Correlation: 0.9988 RMSE: 0.02139 0 7. -20 20 40 Temperature (C)