Hello, please help me answer and explain this exercise in detail. It is about Fluid Mechanics. I would really appreciate it$.$In the following figure, oil is being carried. Assuming that there are no energy losses in the system and the pipes are schedule $40,$ calculate the volumetric flow in $ft\frac{3}{s}$ and the pressure at points $A,B,C$ and D in psia.

$A_1=0\mathrm{.}006f{t}^2$

$A_2=0\mathrm{.}02330f{t}^2$

$D_1=1\mathrm{.}049in$

$D_2=2\mathrm{.}067in$

${}_{?}={53\mathrm{.}68}_{f{t}^3}^{lbm}$

${}_{?}={53\mathrm{.}68}_{f{t}^3}^{lbf}$

$P_1+\frac{1}{2}{v}_1^2+z_1=P_2+\frac{1}{2}{v}_2^2+z_2$