Hello, this is the answer key to this problem. I'm confused as why the final temp of gold is 100C. Why the answer key started from the thermal energy (Eth) of gold instead of bond energy of water(Eb) And how to determine that the final state of H20 is in mixed state but not liquid

ANSWERS WITHOUT AN EXPLANATION WILL RECEIVE NO CREDIT Question 1: A solid block of gold is placed in a freezer filled with steam. Initially, the process starts with 3 kg of steam (gaseous H20) at its boiling point (Tooil = 100 C) and 20 kg of gold (Au) at a temperature of -80C. In 3 hours 1500 kJ of energy are exchanged between the system and the freezer. (a) Determine the final states (temperature and phase) of the H2O and gold. If either substance ends in a mixed phase determine how much mass is in each phase. You may find it useful to draw an energy interaction diagram, but are not required to do so. For Au Step t : DEIn = MCA DJ = 20 - 0.129 - ( 100- 1- 80 ) ) both meat Gold DEJe = 464 . U KJ . phase my Changes T. T(=- 80 c Final state : ( An solid Tg = 100 c Temp : 100'C Mo