Help ASAP

$1)$ Discharge calculations and supporting data

$2)$ Apply the continuity principle to your results. Otter explanations for

measure every $5ft($width$)$

$0\mathrm{.}83ft$

$0\mathrm{.}7f\frac{t}{sec}(.6$ method$)$

$0\mathrm{.}4f\frac{t}{sec}($average method$)$

$1\mathrm{.}49ft$

$2\mathrm{.}1f\frac{t}{sec}(.6$ method$)$

$1\mathrm{.}8f\frac{t}{sec}($average method$)$

$1\mathrm{.}43ft$

$1\mathrm{.}9f\frac{t}{sec}(.6$ method$)$

$1\mathrm{.}8f\frac{t}{sec}($average method$)$

$1\mathrm{.}25ft$

$0\mathrm{.}9f\frac{t}{sec}(.6$ method$)$

$0\mathrm{.}7f\frac{t}{sec}($average method$)$

orange ball method $25ft$ distance

trial $1$

$12\mathrm{.}39sec$

trial $2$

$14sec$

trial $3$

$13\mathrm{.}38$ Sec

avg: $13\mathrm{.}26$SeC

weir

slab $1$

width: $2ft$

length: $5ft10in$

depth: $3\mathrm{.}25$in

slab $2$

width: $1ft11in$

length: $4ft5in$

depth: $3\mathrm{.}75$ in

slab $3$

width: $2ft9in$

length: $4ft4in$

depth: $4\mathrm{.}3$in

slab $4$

width: $2ft10in$

length: $4ft2in$

depth: $5\mathrm{.}3$in

slab $5$

width $2ft9in$

length: $4ft3in$

depth: $4\mathrm{.}5$in

slab $6$

width: $2ft11\mathrm{.}5in$

length: $4ft3$in

depth: $4\mathrm{.}5$ in

slab $7$

width: $3ft1in$

length: $2ft10\mathrm{.}5in$

depth: $5\mathrm{.}75$in

slab $8$

width: $3ft3in$

length: $3ft11\mathrm{.}5in$

depth: $5$ indiscrepancies, if any.