Question: HELP ME!!!!! One Solution No Solutions Infinitely Many Solutions Equation 3 - 5x+ 5 7x-3 = 7x+ 5 7x-3 - Use properties of equality Solve
HELP ME!!!!!
One Solution
No Solutions
Infinitely Many Solutions
Equation
3 - 5x+ 5
7x-3 = 7x+ 5
7x-3 -
Use properties of equality
"Solve"
Check your solution
End Results
YOU TRY!!!
One Solution
No Solutions
Infinitely Many Solutions
Equation
+ 2) = 30
= 45 + 5 c
= 2a4
Use properties of equality
"Solve"
Check your solution
End Results
Identify linear equation solutions without solving
One Solution
No Solutions
Infinitely Many Solutions
Equation
3 - 5x+ 5
3
What can you say about the coefficients of the terms with x in the equation?
What can you say about the
o sta t on both sides of the equation?
In general,
Quick Write
What does it mean to have Que..EQ.LuiiQ.u in a linear equation?
What does it mean to have no solutions in a linear equation?
What does it mean to have iauite.u..na.uu..sgluticus in a linear equation?
Write an equation with Que-EQlu.CiQL n.Q-SQlU.-iQUS and infin itely many solutions.
One Solution
No Solutions
Infinitely Many Solutions
Begin with
Solution: Variable = Constant
False Statement: Constant = Different Constant
True Statement: Constant = Constant
Use properties of equality
add, subtract, Inultiply or divide by the sanie nunmber on both sides
add, subtract, rnultiply or divide by the satne variable on both sides
add, subtract, Inultiply or divide by the saine variable on both sides
Make another change using the distributive property
add, subtract, multiply or divide by-the-another
umb
t
add, subtract, multiply or divide bybe-same.nuxnber on both sides
add, subtract, multiply or divide by the saine
u be
End Results
SPECIAL CASE x O is a one solution answer
One Solution
One Solution
One Solution
Equation
+ 12 X 12
You
True Statement:
Variable = Zero
Use properties of equality
"Solve"
add, subtract, Inultiply or divide by-the-same variable on both sides
Check your solution
add, subtract, tnultiply or divide by.tlxesame
u
End Results
Note: If the coefficients of x are different and the value of the constants are the same, the ONLY SOLUTION IS x =
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