Question 3 Not yet answered Marked out of 1.00 P Flag question To solve we first rewrite the equation in the form. and then It follows that the equation is then we obtain which is is an where A=3 A=-2 y' = ez+y-1 dy dz =e+y-1, (1-e2-y)dr+dy = 0. (z) = e z e (1-e-y)dx + edy = 0, (x) y=ce +2 + A full multiplicator A=-1 If we choose Hence, the function We solve this last problem to obtain A=-3 A=2 A=1 exact not exact integrating factor