Question 3 Not yet answered Marked out of 1.00 P Flag question To solve we first...

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Question 3 Not yet answered Marked out of 1.00 P Flag question To solve we first rewrite the equation in the form. and then It follows that the equation is then we obtain which is is an where A=3 A=-2 y' = e²z+y-1 dy dz =e²+y-1, (1-e2-y)dr+dy = 0. μ(z) = e z e (1-e²-y)dx + e²dy = 0, μ(x) y=ce² +²2² + A full multiplicator A=-1 If we choose Hence, the function We solve this last problem to obtain A=-3 A=2 A=1 exact not exact integrating factor Question 3 Not yet answered Marked out of 1.00 P Flag question To solve we first rewrite the equation in the form. and then It follows that the equation is then we obtain which is is an where A=3 A=-2 y' = e²z+y-1 dy dz =e²+y-1, (1-e2-y)dr+dy = 0. μ(z) = e z e (1-e²-y)dx + e²dy = 0, μ(x) y=ce² +²2² + A full multiplicator A=-1 If we choose Hence, the function We solve this last problem to obtain A=-3 A=2 A=1 exact not exact integrating factor

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