Question 4 Not yet answered Marked out of 1.00 P Flag question To solve y"+y 2y = 2t with the initial values y(0)=0 and we first find the -2t Ye Ce + Det. To get the solution, we assume Since neither assumption will work. Substituting y in the differential equation we obtain and D=1. y=cos A+B particular complementary y=At+B At y (0)=1 y'(0)=2 C=1/2 y(0)=-1 C=1/2 solution nor B are solutions of the homogeneous equation this and B=-1/2. Next, we use the initial conditions and obtain y=A+Bt y(0)=-1) A=-1 A=1