Question: Here is the problem given: Add a method public Sequence mergeSorted(Sequence other) to the Sequence class of Exercise E7.20 that merges two sorted sequences, producing

Here is the problem given:

Add a method public Sequence mergeSorted(Sequence other) to the Sequence class of Exercise E7.20 that merges two sorted sequences, producing a new sorted sequence. Keep an index into each sequence, indicating how much of it has been processed already. Each time, append the smallest unprocessed value from either sequence, then advance the index. For example, if a is 1 4 9 16 and b is 4 7 9 9 11 then a.mergeSorted(b) returns the sequence 1 4 4 7 9 9 9 11 16 If a or b is not sorted, merge the longest prefixes of a and b that are sorted.

And here is the code I got from the website

public Sequence mergeSort(Sequence other) { Sequence sorted = new Sequence(); int valueIndex = 0; int otherIndex = 0; Sequence newSequence = new Sequence(); while(valueIndex < values.size() && otherIndex < other.values.size()) { if(values.get(valueIndex) < other.values.get(otherIndex)) { newSequence.set(values.get(valueIndex)); valueIndex = valueIndex + 1; } else { newSequence.set(other.values.get(otherIndex)); otherIndex = otherIndex + 1; } } while (valueIndex

public static void main(String[] args){ Sequence s1 = new Sequence(); s1.add(5); s1.add(8); s1.add(9) Sequence s2 = new Sequence(); s2.add(4); s2.add(5); s2.add(9); s2.add(15); System.out.println("Sequence: " + s1.toString()); System.out.println("Other sequence " + s2.toString()); System.out.println("The resultant sequence "); Sequence newseq = s1.mergeSort(s2); System.out.println(newseq.toString());

Works great, but I don't understand it. Can you please comment it out and provide a breif explantion of whats going on.

Thanksl

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