Question: Hi, can I have some help with these math questions, please? Volume of Revolutions... Final Assignment Answer the following questions with full solutions, answers are



Hi, can I have some help with these math questions, please?

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Volume of Revolutions... Final Assignment Answer the following questions with full solutions, answers are provided to help you with your work. 1. Find the volume of the solid of revolutions generated by rotating the function y = \\E around the x-axis for the domain [0, 5]. 25%) 2. Find the volume of the solid if it is rotated about the x-axis of y = x3 bounded by the x-axis 1291': andthelinesx = 1o:ndx =2. T) 3. Find the volume of the solid of the function y = x3 if it is rotated about the y-axis, bounded by the y-axis andthe lines y= l andy= S. (as?) 4. Find the volume of the solid of revolution generated by revolving the region enclosed by the _ 2 . Err graphs of y 2x crud y 1: about the y-axm. (?) 5. Find the volume of the solid of revolution generated by revolving the region enclosed by the graphs of y = 2x and y = x2 about the line y = -5. 5 6. Determine the volume of the solid obtained by rotating the region bounded by y = x' - 4x +5, x =1, x = 4 and the x-axis about the x-axis. 5 7. Determine the volume of the solid obtained by rotating the region bounded by y = 2x3, y = 8 and the y - axis about the x - axis. (87.080m)8. Determine the volume of the solid obtained by rotating the portion of the region bounded by y = Vx and y = = that lies in the first quadrant about the y-axis. ($127 21 9. Determine the volume of the solid obtained by rotating the region bounded by y = x2 - 2x and y = x about the line y = 4. (5) 10. Determine the volume of the solid obtained by rotating the region bounded by y = 2vx - 1 and y = x - 1 about the line x = -1. () 11. Find the volume of the solid whose base is the region bounded by y = x2 - 1 and y = 3 and whose cross-sections are equilateral triangles with the base perpendicular to the y-axis. See figure below to see a sketch of the cross-sections. (8v/3) y= 3 y=x- 1 X
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