Hi I need help with this whole question please

(49%) Problem 21: On a one lane road, a person driving a car at v1 = 64 mi/h suddenly notices a truck d= 2.2 mi in front of him. That truck is moving in the same direction at vy = 38 mi/h. In order to avoid a collision, the person has to reduce the speed of his car to v, during time interval At. The smallest magnitude of acceleration required for the car to avoid a collision is a. During this problem, VI assume the direction of motion of the car is the positive direction. Refer to the figure. d theexpertta.com $ 11% Part (a) Enter an expression, in terms of defined quantities, for the distance, Ax,, traveled by the truck during the time interval At. Grade Summary Ax2 = v2 ( v2 - v1/a )| Deductions 0% Potential 100% Submissions 4 5 6 Attempts remaining: 4 (0% per attempt) 1 2 3 detailed view END 0% CLEAR Hints: 1 for a 0% deduction. Hints remaining: 0 Feedback: 0% deduction per feedback. -Use the expression for distance in terms of elapsed time and constant speed $ 11% Part (b) Enter an expression for the distance, Ax]: traveled by the car in terms of v1; v, and a. Ax] = v2" - vi-/(2=) X Attempts Remain Feedback: is available $ 11% Part (c) Enter an expression for the acceleration of the car, a, in terms of v1, Vy, and At. a= vy - V1/At X Attempts Remain Feedback: is available. & 11% Part (d) Enter an expression for Ay in terms of Ax, and d when the driver just barely avoids collision. & 11% Part (e) Enter an expression for Ax in terms of v1; vy, and At. & 11% Part (f) Enter an expression for Ar in terms of d, v1; and vg. 11% Part (g) Calculate the value of At in hours. At = 0.169 - Correct! A 11% Part (h) Use the expressions you entered in parts (c) and (f) and enter an expression for a in terms of d, v1; and v2- $ 11% Part (1) Calculate the value of a in meters per second squared. a = - 153.63 Feedback: You may have forgotten to convert velocities into m's and distance into meters. a=-153.6 X Attempts Remain