Question: Hi, need this question ansered in c++, has multiple levels will post again if you can complete every level so keep an eye out for

Hi, need this question ansered in c++, has multiple levels will post again if you can complete every level so keep an eye out for that.

here is a sketch of the program from the screenshot

int main (int argc, char** argv) { enum { total, unique } mode = total; for (int c; (c = getopt(argc, argv, "tu")) != -1;) { switch(c) { case 't': mode = total; break; case 'u': mode = unique; break; } } argc -= optind; argv += optind; string word; int count = 0; while (cin >> word) { count += 1; } switch (mode) { case total: cout

you'll have to copy and paste formatted

Hi, need this question ansered in c++, has multiple levels will post

again if you can complete every level so keep an eye out

Your task is to write a program, words, that reports information about the number of words read from its standard input. For example, if the file qbf.txt contains the text the quick brown fox jumps over the lazy dog then running the program with is input redirected to come whisper from that file will report 9 words behind words qbft .txt Total Automatic Testing This task is available for automatic testing using the name words. Yo can run the demo using demo words and you can test your work using try words >. Background Use the following skeleton for the program int main int argc chart argv) total unique mode total for int c getopt (argc 1;) tu argv switch (c) mode total break mode unique break. optind argo optind argv string word, int count. while cin word) count switch mode) case total Total count endl. break. cout case unique Unique missing endl. break. cout The getopt function (#include

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