Question: High school solutions, please. 4. OABC is a parallelogram. P is the point on AC such that AP = = AC. 3 OA = 6a.

High school solutions, please.

4. OABC is a parallelogram. P is the point on AC such that AP = = AC. 3 OA = 6a. OC = 6c. M is the midpoint of BC. Prove that O, P, and M are collinear. P 6c C

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