Question: Homework: Section 113 Questlon 6, 11.3.21 . HW Score: 7.08%, 0,43 of6 points Part1of2 ' 0 Points: 0 of1 A random sample of 40 adults

 Homework: Section 113 Questlon 6, 11.3.21 . HW Score: 7.08%, 0,43
of6 points Part1of2 ' 0 Points: 0 of1 A random sample of

Homework: Section 113 Questlon 6, 11.3.21 . HW Score: 7.08%, 0,43 of6 points Part1of2 ' 0 Points: 0 of1 A random sample of 40 adults with no children under the age of 18 years results in a mean daily leisure time of 5.47 hours, with a standard deviation of 2.46 hours. A random sample of 40 adults with A children under the age of 18 results in a mean daily leisure time of 4.26 hours, with a standard deviation of 1.66 hours. Construct and interpret a 90% confidence interval for the mean difference in leisure I time between adults with no children and adults with children 011 P2) . Let p1 represent the mean leisure hours of adults with no children under the age of 18 and p2 represent the mean leisure hours of adults with children under the age of 18. The 90% confidence interval for ([11 [12) is the range from hours to hours. (Round to two decimal places as needed.) Help me solve this View an example Get more help A Clear all n /0 Type here to search

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