How can i get my code below to show Able was I, ere I saw Elba. a strict palindrome attributed to Napoleon

A man, a plan, a canal: Panama! an ordinary palindrome and a not palindrome fixed here is my code #include

#include

#include

#include

#include

using namespace std;

bool is$\_$ordinary$\_$palindrome$($const string& str$)\{$

$//$ make a copy of the input string in which punctuation and spaces are removed and all text is lower case

string copy;

for $($char c : str$)\{$

if $($isalnum$($c$))\{//$ check if the character is alphanumeric

copy $+=$ tolower$($c$,$ locale::classic$())$; $//$ append the lower case version of the character to the new string using the default locale

$\}$

$\}$

$//$ make another copy of the input string in which all text is lower case

string lower $=$ str;

for $($char& c : lower$)\{$

c $=$ tolower$($c$,$ locale::classic$())$; $//$ convert each character to lower case using the default locale

$\}$

$//$ reverse the second copy

reverse$($lower$.$begin$(),$ lower.end$())$;

$//$ compare the first copy with the second copy

return $($copy $==$ lower$)$;

$\}$

bool is$\_$strict$\_$palindrome$($const string& str$)\{$

$//$ make a copy of the input string in which all text is lower case

string lower $=$ str;

for $($char& c : lower$)\{$

c $=$ tolower$($c$,$ locale::classic$())$; $//$ convert each character to lower case using the default locale

$\}$

$//$ make another copy of the input string

string reversed $=$ lower;

$//$ reverse the copy

reverse$($reversed$.$begin$(),$ reversed.end$())$;

$//$ compare the input string with the reversed copy

return $($lower $==$ reversed$)$;

$\}$

bool is$\_$not$\_$palindrome$($const string& str$)\{$

$//$ return the opposite of the ordinary palindrome check

return $!$is$\_$ordinary$\_$palindrome$($str$)$;

$\}$

int main$()\{$

string input;

do $\{$

cout $<<$ "Please enter a string $($Q to quit$)$: $"$;

getline$($cin$,$ input$)$;

if $($input $=="$Q$")\{$

break;

$\}$

if $($is$\_$ordinary$\_$palindrome$($input$))\{$

cout $<<$ "The string is an ordinary palindrome." $<<$ endl;

$\}$

else if $($is$\_$strict$\_$palindrome$($input$))\{$

cout $<<$ "The string is a strict palindrome." $<<$ endl;

$\}$

else if $($is$\_$not$\_$palindrome$($input$))\{$

cout $<<$ "The string is not a palindrome." $<<$ endl;

$\}$

$\}$ while $($true$)$;

return $0$;

$\}$