Question: How did they get 10^6 power when I solved it just 6.21 ...And 10^7. And 10^9 * 10 ^-6 For six, we have n=8, x=6,

How did they get 10^6 power when I solved it just 6.21 ...And 10^7. And 10^9

* 10 ^-6 For six, we have n=8, x=6, and p=.08. n! 8! f (x) = x! (n - x)P*(1 -p)(m-x) = 6! (8 - 6)! 08(1 -.08)(8-6) = 6.2 x 10-6. For six, we have n=8, x=7, and p=.08. n! 8! f ( x) = - x! (n - x);p*(1 -p)(m-x) 7! (8 - 7)! 087(1 - .08) (8-7) = 1.54 x 10-7. For six, we have n=8, x=8, and p=.08. n! 8! f ( x) = = x! (n - x) p*(1 -p)(n-x) 8! (8 - 8)! 088(1 -.08) (8-8) = 1.68 x 10-9. So, the probability of six, seven, or eight failing: 6.2 x 10 6 + 1.54 x 10-7 + 1.68 x 10-9 = 6.355 x 10-6

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