How do I solve this?

where do I get q to do : q= m.cp.T

May I have the steps to this please?

A student performed the first determination in Part 1. They reacted 61.06g of 1M HCl with 0.1997g of magnesium. The temperature before mixing was 19.8C and the temperature after mixing was 34.0C. Calculate the heat capacity (Cp) of the final solution based on this student's data. Report your final answer, in J/K, to the nearest integer, and only include the numerical value (no units). Do not use scientific notation for this question. on each graph. Calculations Part 1 - The Reaction of Magnesium with Hydrochloric Acid 1. The specific heat of the final solution is 3.92JK1g1 The heat capacity of the final contents of the calorimeter, Cp, is given by: Cp(J1)=specificheatmass=3.92JK1g1massusedof1MHCl(aq) 2. Neglecting the heat capacity of the calorimeter assembly, the measured heat flow, q, for equation (11) is: qmn(J)=Cp(JK1)T(K) 3. Calculate the number of moles of Mg metal used (the limiting reactant). 4. Finally, q per mole of Mg for the reaction represented by equation (11) is: H11=qrxn(measured,,J)+nMg(mol)=H,ofMg2+(aq) Part 2 - The Reaction of Magnesium Oxide with Hydrochloric Acid 1. The specific heat of the final solution is 3.92JK1g1 The heat capacity of the final contents of the calorimeter, Cp, is given by: Cp(JK1)=specificheatmass=3.92JK1g1massusedof1MHCl(aq) 2. Calculate q(xn. 3. Calculate the number of moles of MgO reacted (limiting reactant). 4. H12=qnn (measured )nM9O 5. Calculate H, of MgO(s), using equation (13)