Question: How does this arbitrary constant affect it? If x(1) * g(1) = c(1), then show that x(ar) glat) = [1/alc(ar). This time-scaling property of convolution

How does this arbitrary constant affect it?

If x(1) * g(1) = c(1), then show that x(ar) glat) = [1/alc(ar). This time-scaling property of convolution states that if both x(r) and g() are time-scaled by a, their convolution is also time-scaled by a (and multiplied by [1/al)

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