Question: How many combinations would be required to achieve decision/condition coverage in the following code? void myMin( int x, int, y, int z ) { int
How many combinations would be required to achieve decision/condition coverage in the following code?
void myMin( int x, int, y, int z )
{ int minimum = 0; if ( ( x <= y ) && ( x <= z) ) minimum = x; if ( ( y <= x ) && ( y <= z ) ) minimum = y; if ( ( z <= x ) && ( z <= y ) ) minimum = z; else minimum = -99; return minimum; }
Step by Step Solution
There are 3 Steps involved in it
Get step-by-step solutions from verified subject matter experts
