How many computers? In a simple random sample of 150 households, the sample mean number of personal computers was 1,56. Assume the population standard deviation is o = 0.82. Part: 0 / 4 Part 1 of 4 (a] Construct a 95% confidence interval for the mean number of personal computers. Round the answer to at least two decimal places, A 95% confidence interval for the mean number of personal computers is X Part: 1 / 4 Part 2 of 4 (b) If the sample size were 125 rather than 150, would the margin of error be larger or smaller than the result in part (a]] Explain. The margin of error would be (Choose one) . since (Choose one) |in the sample size will (Choose one) . the standard error.Part: 2 / 4 Part 3 of 4 (c) If the confidence levels were 98% rather than 95%, would the margin of error be larger or smaller than the result in part (a]? Explain. The margin of error would be (Choose one) V , since (Choose one) | in the confidence level will (Choose one) the critical value Part : 3 / 4 Part 4 of 4 (d) Based on the confidence interval constructed in part (a), is it likely that the mean number of personal computers is greater than 1.817 It (Choose one) |likely that the mean number of personal computers is greater than 1.81 . X