Question: How to solve? Let f(a) = 38 -202 The slope of the tangent line to the graph of f(a) at the point (-6, 2) is

How to solve?

Let f(a) = 38 -202 The slope of the tangent line to the graph of f(a) at the point (-6, 2) is The equation of the tangent line to the graph of f(x ) at (-6, 2) is y = max + b for m and b Hint: the slope is given by the derivative at x = -6, ie. f(- 6+ h) -f(-6) lim h-+0 h
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