How to solve this calculus question?

Consider the definite integral 5 cosh(6:c) I =f dm 0 9 cosh2 (62:) sinh(6a:) (a) Without performing any simplification inside the integral, rewrite the denominator using a hyperbolic identity. in terms of sinh(6m) alone. The denominator becomes = E. (b) Substitute sinh(6a:) = t . Hence, we have that _ bi _ a PU) with a= no b= IE1 PU) = ID (c) We could then compute I by applying the partial fraction decomposition to the integrand 1/P(t). How many terms do we expect in the decomposition? number of terms = E]