Question: How would I prove that log 2 (3 2n ) = O(n) (Big Oh of N) I got: 2 log 2 (3) n

How would I prove that log2(32n) = O(n) (Big Oh of N)

I got: 2 log2(3) n <= c * n , however, I do not know how to continue from this part.

Thanks

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