I A horizontal elutriator is a simple device that is sometimes used at the inlet to an APCS to remove some of the larger diameter particles from the air. It consists of parallel horizontal plates, as sketched. Dirty air enters from the left at low air speed. As the air moves along, particles fall and settle on the plates. We assume that when the particles hit the plate, they stick there and remain on the plate - they are removed from the air. After some time, the device may get clogged, so it needs to be washed out. However, there are no moving parts, it does not require electricity, and it is simple and effective at removing particles from the air. Heavier and/or larger particles settle quickly, while lighter and/or smaller particles take longer to settle. Therefore, we expect the removal efficiency of the device to depend on particle diameter and particle density. For simplicity, consider SATP conditions with the incoming dirty air consisting of a wellmixed polydisperse aerosol of spherical ash particles of density p=1676kg/m3 with diameters ranging from 0.1 to 10 microns. Air flows at an average speed of U=0.126m/s through the channels, the flow is laminar in the channels, the length of the horizontal elutriator is 0.796m and the channel height between plates is H=1.22mm. For best accuracy in your calculations, be sure to include the Cunningham correction factor and iterate as usual. (a) Calculate the critical diameter, defined as the minimum particle diameter at which we predict 100\% removal through the elutriator. In other words, particles greater in size than this critical diameter will all settle out and be removed, whereas particles smaller than this critical diameter will be only partially removed (efficiency less than 100\%). You may have to do some iteration. Your answer should lie between 1 and 2 microns if you do the calculations correctly. Give your answer to at least 3 significant digits