I. A statistician randomly sampled 25 observations from a normally distributed population. The descriptive statistics are given below: n = 25, X = 10, s = 5 You are required to estimate the population mean with 90 percent confidence. Please answer the following questions: (Note that to.05, 24=1.711 and Zo.05=1.645) 1. The point estimate of the population mean () is (type the value here):= 2. The appropriate confidence interval is because and we 3. Compute 90 percent confidence interval and type the values of lower confidence limit and upper confidence limit below (round up to two decimal places): . Lower Confidence Limit:= . Upper Confidence Limit:=|l. Now the statistician takes a random sample of 25 observations from another normally distributed population. The descriptive statistics are given below: n=25.)_{=10.o=5 You are required to estimate the population mean with 90 percent condence. Please answer the following questions: (Note that \"105:1 .71 1 and 2013551 .645} because 'l. The appropriate condence interval is' A v and we A v 2. Compute the 90 percent condence interval and type the values of lower condence limit and upper condence limit below (round up to two decimal places): 0 Lower Condence Limit:= 0 Upper Condence Limit:= III. From the condence intervals estimated in part (I) and (II): The tinterval estimated is wider than zinterval. The extent to which tdistribution is more spread out than the zdistribution is determined by A v