I cant figure out how to fix this error that i keep getting the pointer to object type i put the code a long with the error i keep getting this is C++

  

   

Transcribed Image Text:

1 TM st in 1000 2 3 4 5 6 Eclass Demo 7 8 9 10 11 224 12 13 14 15 16 17 18 19 20 21 222222 23 24 25 26 27 28 29 a m m m m m m 31 32 WN 33 #include #include #include #include 34 35 { private: //variable declare// 30 Evoid Demo::ADD() int Number1[255], Number2 [255], ADD[255]; char S1[255], $2[255]; int L1, L2; public: Demo () {}; void ADD(); //FUNCTION ADD// using std::cin; cin >> 51;//input the 2 numbers as string 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 LEF cin >> S2; //convert character to integer// for (L1 } for (L2 } = Number1[L1] = $1[L1] - 0 ; 0; S1[L1] != \0 ; L1++) = = 0; 52[L2] != \0 ; L2++) Number2 [L2] int carry = 0; int k 0; int i = L1 1; int j = L2 1; - = if (L1 > L2) 52 [L2] 0 ; for (; i >= 0 && j >= 0; i--, j--, k++) { ADD[k] (Number1[i] + Number2[j] + carry) % 10; carry = (Number1[i] + Number2[j] + carry) / 10; 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 } while (i > 0) { = ADD [k++] carry = else { (Number1[i] + carry) % 10; (Number1[i] + carry) / 10; else if (L1 < L2) { = while (j >= 0) { ADD [k++] = (Number2[j] + carry) % 10; carry (Number2[j--] + carry) / 10; = if (carry > 0) ADD [k++] = carry; } using std::cout; cout < < SUM OF THE TWO LARGE NUMBER = for (k--; k >= 0; k--) cout < < ADD[k]; 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 int main() { } using std::cout; using std::endl; cout < < endl; cout < < ENTER NUMBER TO CALCULATE ADDITION OF TWO LARGE NUMBERS. < < endl; Demo X; //CREATING INSTANCE // X.ADD();//CALLING ADD FUNCTION// system( PAUSE ); return 0; 1 TM st in 1000 2 3 4 5 6 Eclass Demo 7 8 9 10 11 224 12 13 14 15 16 17 18 19 20 21 222222 23 24 25 26 27 28 29 a m m m m m m 31 32 WN 33 #include #include #include #include 34 35 { private: //variable declare// 30 Evoid Demo::ADD() int Number1[255], Number2 [255], ADD[255]; char S1[255], $2[255]; int L1, L2; public: Demo () {}; void ADD(); //FUNCTION ADD// using std::cin; cin >> 51;//input the 2 numbers as string 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 LEF cin >> S2; //convert character to integer// for (L1 } for (L2 } = Number1[L1] = $1[L1] - 0 ; 0; S1[L1] != \0 ; L1++) = = 0; 52[L2] != \0 ; L2++) Number2 [L2] int carry = 0; int k 0; int i = L1 1; int j = L2 1; - = if (L1 > L2) 52 [L2] 0 ; for (; i >= 0 && j >= 0; i--, j--, k++) { ADD[k] (Number1[i] + Number2[j] + carry) % 10; carry = (Number1[i] + Number2[j] + carry) / 10; 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 } while (i > 0) { = ADD [k++] carry = else { (Number1[i] + carry) % 10; (Number1[i] + carry) / 10; else if (L1 < L2) { = while (j >= 0) { ADD [k++] = (Number2[j] + carry) % 10; carry (Number2[j--] + carry) / 10; = if (carry > 0) ADD [k++] = carry; } using std::cout; cout < < SUM OF THE TWO LARGE NUMBER = for (k--; k >= 0; k--) cout < < ADD[k]; 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 int main() { } using std::cout; using std::endl; cout < < endl; cout < < ENTER NUMBER TO CALCULATE ADDITION OF TWO LARGE NUMBERS. < < endl; Demo X; //CREATING INSTANCE // X.ADD();//CALLING ADD FUNCTION// system( PAUSE ); return 0;