I have 5 kg of ice @ -10 degrees Celsius. How much heat (in Joules) do I need to: A: Bring that to 5 kg of ice @ 0 degrees Celsius B: Change it from 5 kg ice 0 degrees to 5 kg Water @ 0 degrees. C. Bring the 5 kg water from 0 degrees to 10 degrees Celsius. Remember the latent heat for the phase change is 80 cal/g or 80 Cal/kg (1 Cal= 1000 cal) and ( 1 Cal = 4186 J)

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To calculate the heat required for each step we need to use the specific heat capacity and latent he... View the full answer