Question: I have already figured out all the problems in this picture. I am just including it for reference. Here are the problems I need help
I have already figured out all the problems in this picture. I am just including it for reference.

Here are the problems I need help with:
Thank you!
In the previous problem, a randomized double-blind experiment was done to test the effectiveness of a drug designed to improve memory in Alzheimer's patient. Suppose the experiment was repeated and a 3rd group was added, no drug or placebo. Here's the results: Drug group: 7, 1, 8, 9 Placebo group: -2, 5, 1 Nothing group: -1, 0, -2 Null Hypothesis: No difference between any of the groups in the population Alternative Hypothesis: At least one of the groups is different in the population a. Fill out the chart below: First combine into one ordered list: -2, -2, -1, 0, 1, 1, 5, 7, 8, 9 Observed Rank Sum 32.5 Expected Rank Sum 22.0 Computer's answer now shown above. You are correct. Your receipt no. Is 152-45507 Computer's answer now shown above. You are correct. Your receipt no. is 152-178 Observed-Expected 10.5 Computer's answer now shown above. You are correct Your receipt no. is 152-5563 Drug group Previous Tries Previous Tries Previous Tries 16.5 Placebo Group 14.0 Computer's answer now shown above. You are correct. Your receipt no. is 152-50542 Computer's answer now shown above. You are Previous Tries correct. Previous Tries -2.5 Computer's answer now shown above. You are correct. Your receipt no. is 152-6693 Previous Tries Your receipt no. is 152-4738 8.5 -8.0 Nothing group Computer's answer now shown above. You are correct. Your receipt no. is 152-5595 2 Previous Tries 16.5 Computer's answer now shown above. You are correct. Your receipt no. is 152-8489 > Previous Tries Computer's answer now shown above. You are correct. Your receipt no. is 152-173 Previous Tries 55 o Total Computer's answer now shown above. You are correct. Your receipt no. is 152-81222 Previous Tries 55 Computer's answer now shown above. You are correct. Your receipt no. Is 152-3064 ? Previous Tries Computer's answer now shown above. You are correct. Your receipt no. is 152-2013 Previous Tries (obsR -expr.) b. Find H 12 N(N+1) = 5.56 ni Computer's answer now shown above. You are correct. Previous Tries Your receipt no. is 152-9640 c. Since the samples sizes are small, what test-statistic can we use to compute p-values? Use the H stat but look up the critical values on the F curves Use the H stat and look up its exact probability distribution on tables Use the H stat but look up the critical values on the Chi Square curves with df=g-1 Submit Answer Tries 0/2 d. Let's assume the sample sizes were large enough so we can approximate the H stat with the Chi square curves. To find p-value, look at the Chi square curve with degree of freedom. Submit Answer Tries 0/2 What is the critical value of chi-square at a = 0.05? Submit Answer Tries 0/2 What do you conclude? Reject the null hypothesis Fail to reject the null hypothesis Submit Answer Tries 0/1 In the previous problem, a randomized double-blind experiment was done to test the effectiveness of a drug designed to improve memory in Alzheimer's patient. Suppose the experiment was repeated and a 3rd group was added, no drug or placebo. Here's the results: Drug group: 7, 1, 8, 9 Placebo group: -2, 5, 1 Nothing group: -1, 0, -2 Null Hypothesis: No difference between any of the groups in the population Alternative Hypothesis: At least one of the groups is different in the population a. Fill out the chart below: First combine into one ordered list: -2, -2, -1, 0, 1, 1, 5, 7, 8, 9 Observed Rank Sum 32.5 Expected Rank Sum 22.0 Computer's answer now shown above. You are correct. Your receipt no. Is 152-45507 Computer's answer now shown above. You are correct. Your receipt no. is 152-178 Observed-Expected 10.5 Computer's answer now shown above. You are correct Your receipt no. is 152-5563 Drug group Previous Tries Previous Tries Previous Tries 16.5 Placebo Group 14.0 Computer's answer now shown above. You are correct. Your receipt no. is 152-50542 Computer's answer now shown above. You are Previous Tries correct. Previous Tries -2.5 Computer's answer now shown above. You are correct. Your receipt no. is 152-6693 Previous Tries Your receipt no. is 152-4738 8.5 -8.0 Nothing group Computer's answer now shown above. You are correct. Your receipt no. is 152-5595 2 Previous Tries 16.5 Computer's answer now shown above. You are correct. Your receipt no. is 152-8489 > Previous Tries Computer's answer now shown above. You are correct. Your receipt no. is 152-173 Previous Tries 55 o Total Computer's answer now shown above. You are correct. Your receipt no. is 152-81222 Previous Tries 55 Computer's answer now shown above. You are correct. Your receipt no. Is 152-3064 ? Previous Tries Computer's answer now shown above. You are correct. Your receipt no. is 152-2013 Previous Tries (obsR -expr.) b. Find H 12 N(N+1) = 5.56 ni Computer's answer now shown above. You are correct. Previous Tries Your receipt no. is 152-9640 c. Since the samples sizes are small, what test-statistic can we use to compute p-values? Use the H stat but look up the critical values on the F curves Use the H stat and look up its exact probability distribution on tables Use the H stat but look up the critical values on the Chi Square curves with df=g-1 Submit Answer Tries 0/2 d. Let's assume the sample sizes were large enough so we can approximate the H stat with the Chi square curves. To find p-value, look at the Chi square curve with degree of freedom. Submit Answer Tries 0/2 What is the critical value of chi-square at a = 0.05? Submit Answer Tries 0/2 What do you conclude? Reject the null hypothesis Fail to reject the null hypothesis Submit Answer Tries 0/1