I have the  code, Can you debugged it to meet  the following requirements?

 

You can use any sentence to test, I will then tested with the ones I created. 

 

* Please do not change the structure of the function drastically. I need to learn how to work the Buggs on it, if you change or if you create your own better version, it it wont be the same. 

 

If I run it as it its the first bug is about the object does not have attribute count. 

I did divide using list() so not sure why is this happening. 

 

- Once that is done, run it again and If there is another bug fix that one two. This lesson is about debugging the function. 

 

 

 

I have already have my samples of the sentences to read, I just need a functioning code to test it against. 

 

 

Can you please help me with the bugs and explain me how you resolved them for future references? 

def count_letter_e(loc, count_accented = True, count_uppercase = True):    # Open and read the file    with open(loc+".txt", encoding = "utf-8") as test_file:        text = test_file.read()        test_file = test_file.list()#to change from objet     # List of all e's to look for    e_list = ['e', 'é', 'ê', 'è', 'E', 'É', 'Ê', 'È']    #dictionary with all e counts    letter_counts = {}    for e in e_list:        letter_counts[e] = test_file.count('e')    # Variable that will return the desired integer    sum_counts = 0    if count_uppercase and count_accented:        # When ignoring everything, we want to add up all the counts        text = text.lower()        sum_counts = sum(letter_counts)    elif count_accented == True and count_uppercase == False:        # When ignoring accents, we want to add up the relevant counts        e_counts = [letter_counts[ell] for ell in e_list]        sum_counts = sum(e_counts)    elif count_uppercase == False and count_accented == True:        # When ignoring case, we want to add up the relevant counts        e_counts = [letter_counts[ell] for ell in e_list]        sum_counts = sum(e_counts)    elif count_uppercase == False and count_accented == False:        # When not ignoring anything, we want to count the 'e's        count = text.count('e')    return(sum_counts)

 

Input: o o O loc - a filename as a string with extension ".txt" count_accented) - a boolean value indicating if e is to be counted the same as e.g. (default: True) - all accented e's are counted as a regular unaccented e) count_uppercase - a boolean value indicating if capitalized E's are to be counted in addition to lowercase e's (default: True all uppercase e's are counted as well as lowercase) Output: The count of e's in the text following the rules of the accents and cases.