Question: I have this DE : 4 ty = 1 - H (T - b ) With y (0 ) = 4'10 ) = 0 and

I have this DE : 4" ty = 1 - H (T - b ) With y (0 ) = 4'10 ) = 0 and I get y(T ) = 1 9 y (S ) 3 = 1 - GOST - HIT- 6) [ 1- cos(T-bj ] then how can I show for tob, the corresponding y(T ) can be written as y(T ) = Asin (T - 8 ), that is, the SHM, and what is the amptitude A and the phases

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