I have this engineering maths question which i cannot wrap my head around. i'd be grateful for some help :)

A shaped concrete gutter overhangs the edge of a building. A section through this is shown below. An engineer wishes to work out the turning moment. AM, of the gutter about the pivot shown (thick, black line). 0 Being confident at maths, they set up the following integral: L [VI 2 pg f 3144(113) dzc, 0 where p is the density of concrete (2,400 kg ms), 9 is the acceleration due to gravity (9.81 m 3'2), L is the length of overhang of the structure, and A (3;) describes how the cross-sectional area changes along the w-axis. For this particular structure, the cross sectional area varies as A (3:) = A063, where A0 is the crosssectional area at 32:0, as indicated in the above diagram. 3 The engineer measures L=O.19 m and A0=0.012 m2. :What is the moment 1V1? Give your answer to 2 decimal places. \\Ienw ,,,A,,-,,L, A.,,,,; LA H. M