Question: I have to do this in recursive approach format should be (Python 2.7) def zeros (s): # count how many zeros in string def ones

 I have to do this in recursive approach format should be

I have to do this in recursive approach

format should be (Python 2.7)

def zeros (s):

# count how many zeros in string

def ones (s):

# count how many ones in string

def _main():

s =sys.argv[1]

zero = zeros(s)

one = ones(s)

total = zero + one

stdio.writef(...)

if __name__ == '__main__':

_main()

Problem 2. Implement the functions zeros ) and ones) inbits.py that takes a bit string (i.e., a string of zeros and ones) s as argument and returns the number of zeros and ones in s, each computed recursively. The number of zeros in a bit string is 1 or 0 (if the first character is 'o or '1') plus the number of zeros in the rest of the string; number of zeros of an empty string is 0 (base case). The number of ones in a bit string can be defined analogously. gapython bi tongy 10100 0210911010111 zeros-11, ones- 14, total-25

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