$($i$)$ intercepts ins satio $2$:$5$ Let, $2K$ and $5k$ and the point $(1,-4)$ By Intercept form, and $b=5k\frac{x}{a}+\frac{y}{b}=1(x,y)=(1,-4)\frac{1}{2k-1}-\frac{4}{5k}=1\frac{5k-8k}{10k^2}=15k-8k=10k^2(1)$ intorepts in satio $2$:$5$ let, $2k$ and $5k$ and the pent $(1,-4)$ and $b=5k$ By Intercept form, $\frac{x}{a}+\frac{y}{b}=1(x,y)=(1,-4)\frac{1}{2k}-\frac{4}{2k}=1\frac{5k-8k}{10k^2}=15k-8k=10k^2-3k=10k^{2}10k^2-3$kfind the value of k $-3k=10k^{2}10k^2-3k$