Question: I ' m currently working on reverse engineering phase _ 2 of a challenge, and I ' m having trouble understanding the assembly code. Additionally,

I'm currently working on reverse engineering phase_2 of a challenge, and I'm having trouble understanding the assembly code. Additionally, I need assistance with extracting the six numbers provided as input. Here's the assembly code for phase_2:
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0x400f10 push %rbx
0x400f11 sub $0x20,%rsp
0x400f15 mov %rsp,%rsi
0x400f18 callq 0x40135b
0x400f1d cmpl $0xe,(%rsp)
0x400f21 jne 0x400f2a
0x400f23 mov $0x1,%ebx
0x400f28 jmp 0x400f40
0x400f2a callq 0x401728
0x400f2f jmp 0x400f23
0x400f31 callq 0x401728
0x400f36 add $0x1,%rbx
0x400f3a cmp $0x5,%rbx
0x400f3e je 0x400f52
0x400f40 mov (%rsp,%rbx,4),%eax
0x400f43 sub -0x4(%rsp,%rbx,4),%eax
0x400f47 mov %ebx,%edx
0x400f49 imul %ebx,%edx
0x400f4c cmp %edx,%eax
0x400f4e jge 0x400f36
0x400f50 jmp 0x400f31
0x400f52 add $0x20,%rsp
0x400f56 pop %rbx
0x400f57 retq
000000000040135b :
40135b: 4883 ec 08 sub $0x8,%rsp
40135f: 4889 f2 mov %rsi,%rdx
401362: 488d 4e 04 lea 0x4(%rsi),%rcx
401366: 488d 4614 lea 0x14(%rsi),%rax
40136a: 50 push %rax
40136b: 488d 4610 lea 0x10(%rsi),%rax
40136f: 50 push %rax
401370: 4c 8d 4e 0c lea 0xc(%rsi),%r9
401374: 4c 8d 4608 lea 0x8(%rsi),%r8
401378: be a2274000 mov $0x4027a2,%esi
40137d: b800000000 mov $0x0,%eax
401382: e8 a9 f8 ff ff callq 400c30<__isoc99_sscanf@plt>
401387: 4883 c410 add $0x10,%rsp
40138b: 83 f805 cmp $0x5,%eax
40138e: 7e 05 jle 401395
401390: 4883 c408 add $0x8,%rsp
401394: c3 retq
401395: bf 01000000 mov $0x1,%edi
40139a: e8 e1 f8 ff ff callq 400c80
I understand the basic structure of the function, but I'm struggling with some specific parts, such as the conditional jumps and the use of registers. Additionally, I need help extracting the six numbers provided as input by the read_six_numbers function.
Could someone please assist me in extracting the six numbers?
Thank you very much for your help!

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