Question: I need help Given the function g(:1:) = 4:133 + 6:52 72:13, find the first derivative, 91$} W) = :1 Notice that g'(:1:) = 0

I need help

I need help Given the function g(:1:) = 4:133 + 6:52 72:13,

Given the function g(:1:) = 4:133 + 6:52 72:13, find the first derivative, 91$} W) = :1 Notice that g'(:1:) = 0 when :1: = 2, that is, g'(2) = 0. Now, we want to know whether there is a local minimum or local maximum at :1: = 2, so we will use the second derivative test. Find the second derivative, 9' '.(a:) 9' W = :1 Evaluate g' '.(2) W) =:] Based on the sign of this number, does this mean the graph of g(:1:) is concave up or concave down at :1: = 2? [Answer either up or down -- watch your spelling!!] At a: = 2 the graph of g(a:) is concave :] Based on the concavity of g(a:) at :1: = 2, does this mean that there is a local minimum or local maximum at :1: = 2? [Answer either minimum or maximum -- watch your spelling!!] At a: = 2 there is a local :]

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