Please help!

Given the function g() = 4x3 + 18x2 - 120x, find the first derivative, 9 (z). 9 (2) - Notice that g'(z) = 0 when x - - 5, that is, g'( - 5) = 0. Now, we want to know whether there is a local minimum or local maximum at - - 5, so we will use the second derivative test. Find the second derivative, g' '(x). 9 (2) Evaluate g ( - 5). g '( - 5) = Based on the sign of this number, does this mean the graph of g(z) is concave up or concave down at z - - 57 [ Answer either up or down -- watch your spelling!!] At z = - 5 the graph of g(x ) is concave Based on the concavity of g(x ) at a - - 5, does this mean that there is a local minimum or local maximum at z = - 5? [Answer either minimum or maximum -- watch your spelling!!] At I - - 5 there is a local